Question

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Answer 1

$\huge\underline\bold\blue{Question}$
$\sqrt{4 + 3 \sqrt{ - 20} } + \sqrt{4 - 3 \sqrt{ - 20} }$
$\huge\underline\bold\blue{Answer:-}$

Prove that [math]\sqrt{4+3\sqrt{-20}} + \sqrt{4-3\ sqrt{-20}} = 6[/math]. To make this answer somewhat interesting, I'll suppose I had no idea bro...

Answer 2

Step-by-step explanation:

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