Question

Please solve this question with proper steps, hope you give the correct answer friends

Answer 1

Step-by-step explanation:

Given:Angle ACB = 40°

Tofind:Angle ADB

SOL: Angle DAC = 40° (Alternate Interior angles)

As we know diagonals of rhombus bisects each other at 90°

So,Angle APD = 90°

By angle sum property of Triangle

Angle DAC + Angle APD +Angle ADP = 180°

40° + 90° + Angle ADP= 180°

Angle ADP=180°-130°

Angle ADP=50°

Hope this helps

Please mark the answer brainliest

Answer 2

Answer:

ABCD is a rhombus

angle APB=90° , bcoz in rhombus bisectors intersects at 90°

opposite anglesof rhombus are equal

40°=angle PAB

40° =angle PAD (alt. int. an.)

angle DAB= 40°+40°=80°

In ∆PAB

40°+90°+ angle PBA=180°

angle PBA = 180°-130°=50°

In ∆DAB

50°+80°+angle ADB=180°

angle ADB= 180°-130°=50°

Hope it helps.....