Math, asked by asritadevi2344, 9 months ago

please solve this
 \frac{4 \times  {9}^{2} \times  {15}^{2} \times   {4}^{3}   }{ {2}^{3} \times 5 \times  {6}^{2} \times 2 \times  {3}^{2}   }

Answers

Answered by tapatidolai
16

\frac{4 \times {9}^{2} \times {15}^{2} \times {4}^{3} }{ {2}^{3} \times 5 \times {6}^{2} \times 2 \times {3}^{2} }</p><p>

 =    \frac{4(9 \times 9) (15 \times 15)(4 \times 4 \times 4)}{(2 \times 2 \times 2) 5 (6 \times 6) 2 (3 \times 3)}

 =   \frac{4 \times 81 \times 225 \times 64}{8 \times 5 \times 36 \times 2 \times 9}

 =    \frac{4665600}{25920}

 =  180

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Answered by aayyuuss123
11

Answer:

I think it helps you........

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