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priyanshupatel83:
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20 minutes is the answer
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Let's consider AB to be h. Then,
BD=h/tan30∘=h√3
BC=h/tan60∘=h/√3
CD=BD−BC=2h/√3
If the speed of the boat is x metres per second,
CD=2h/3=600x⟹h/x underoot3=300
Time in which the boat travels distance BC is :
BCx=h/x underoot3=300 sec
Hence, the boat takes 300 seconds or 5 minutes to reach the shore. In total, it takes 15 minutes to cover distance BD.
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