Question

Please tell it fast tommorow is my paper please

​

Answer 1

Answer:

proved above

Step-by-step explanation:

Given data :

Δ ABC is a right Δ and also isosceles triangle.,  

To prove:

AB^2=2 AC^2

Step 1:

Proof:

Here,  

Hypotenuse = AB

Also, as it is given that, ΔABC is isosceles,  

Step 2:

AC = BC   [equal sides of isosceles Δ]  

Using Pythagoras theorem,  

Step 3:

In Δ ABC, we have ;

AB2=AC2+BC2

AB2=AC2+AC2

[AC = BC]  

\mathrm{AB}^{2}=2 \mathrm{AC}^{2}

Hence proved