Question

please tell me answer fast
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Answer 1

Answer:

this is not my standard question

Answer 2

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$\: \bullet \bf{question \to \: ({ \frac{4}{9} })^{4} \times ({ \frac{4}{9} })^{ - 7} = ({ \frac{4}{9} })^{2x - 1} }$

$\sf{\underline{\underline{\large{\bold{Answer:-}}}}}$

$\: \\ \longrightarrow \displaystyle \sf{ \bigg( { \frac{4}{9} } \bigg)^{4} \times \bigg({ \frac{4}{9} } \bigg)^{ - 7} = \bigg({ \frac{4}{9} } \bigg)^{2x - 1} }$

$\longrightarrow \displaystyle \sf{ \bigg({ \frac{4}{9} } \bigg)^{4 + ( - 7)} = \bigg({ \frac{4}{9} } \bigg)^{2x - 1} }$

$\longrightarrow \displaystyle \sf{ \bigg( { \frac{4}{9} } \bigg)^{ - 3} = \bigg({ \frac{4}{9} } \bigg)^{2x - 1} }$

$\: \longrightarrow \displaystyle \sf{ \bigg( { \frac{4}{9} } \bigg)^{ - 3} = \bigg( { \frac{4}{9} } \bigg)^{2x - 1} }$

$\: \longrightarrow \displaystyle \sf{ - 3 = 2x - 1}$

$\: \longrightarrow \displaystyle \sf{ - 3 - 2x + 1 = 0}$

$\: \longrightarrow \displaystyle \sf{ - 2x - 2 = 0}$

$\: \: \longrightarrow \displaystyle \sf{ - 2x = 2}$

$\: \: \longrightarrow \displaystyle \sf{x = \frac{ - 2}{2} \: = \cancel\frac{ - 2}{2} - 1}$

$\: \\ \leadsto \boxed{ \boxed{ \displaystyle \sf{option \: (b) \: \: x = - 1 \: is \: the \: answer}}}$

•Additional information :

$\: \: \bigstar \underline{\boxed{ \sf{ \: by \: law \: of \: indices}}}$

$\bullet \displaystyle \bf{ {a}^{m} \times {a}^{n} = {a}^{m + n} }$

$\: \bullet \displaystyle \bf{( { {a}^{m} })^{n} = {a}^{mn} }$

$\: \bullet \displaystyle \bf{ ({ab})^{m} = {a}^{m} {b}^{m} }$