Please tell me fast. please tomorrow is my exam of maths
Q 2 .
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badalolihan1234:
in which class u r
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Answered by
1
Answer:
,bad=50+90+x=180
140+x=180
x=40 degree because ,bae is given us 50 degree and ,adb = 90 degree and summ of angles of triangle is 180 degree
ab bisects ,a so ,dac=40 and we know that sum of the interior angles=exterior angle of triangle so if ,dac=40
,dac+,acd=90 40+,acd=90
,acd=50 degree
Answered by
0
☺Here is your answer
1) . in triangle ABD
B = 50°
&. ANGLE ADB = 90°
SO, 50 + 90 + BAD = 180
SO, BAD = 40° ANS
2). IN ABOVE QUS , WE HAVE seen BAD =40°
so, CAD = BAC - BAD
SO, CAD = 90-40= 50°
3). IN ACD
BY SUM OF ALL ANGLE OF TRIANGLE -
DAC + BCA+ 90 = 180
SO, BCA = 40°
☺☺HOPE IT HELPS YOU ☺☺
1) . in triangle ABD
B = 50°
&. ANGLE ADB = 90°
SO, 50 + 90 + BAD = 180
SO, BAD = 40° ANS
2). IN ABOVE QUS , WE HAVE seen BAD =40°
so, CAD = BAC - BAD
SO, CAD = 90-40= 50°
3). IN ACD
BY SUM OF ALL ANGLE OF TRIANGLE -
DAC + BCA+ 90 = 180
SO, BCA = 40°
☺☺HOPE IT HELPS YOU ☺☺
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