Math, asked by divyanshi1093, 1 year ago

Please tell me fast. please tomorrow is my exam of maths
Q 2 .

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badalolihan1234: in which class u r

Answers

Answered by badalolihan1234
1

Answer:


,bad=50+90+x=180

140+x=180

x=40 degree because ,bae is given us 50 degree and ,adb = 90 degree  and summ of angles of triangle is 180 degree

ab bisects ,a so ,dac=40 and  we know that sum of the interior angles=exterior angle of triangle so if ,dac=40

,dac+,acd=90 40+,acd=90

,acd=50 degree



badalolihan1234: is it correct
Answered by Abhishek63715
0
☺Here is your answer

1) . in triangle ABD

B = 50°
&. ANGLE ADB = 90°

SO, 50 + 90 + BAD = 180

SO, BAD = 40° ANS

2). IN ABOVE QUS , WE HAVE seen BAD =40°

so, CAD = BAC - BAD

SO, CAD = 90-40= 50°

3). IN ACD
BY SUM OF ALL ANGLE OF TRIANGLE -
DAC + BCA+ 90 = 180
SO, BCA = 40°
☺☺HOPE IT HELPS YOU ☺☺

divyanshi1093: wrong
divyanshi1093: Its wrong
divyanshi1093: Recheck please
divyanshi1093: Chuk de pathe
divyanshi1093: now ok
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