Question

please tell me the answer in detail​

Answer 1

Answer:

Given $f(x)=x^{3}+ax^{2} -2x+a+6$

and ( x+a ) is zero of the polynomial f(x).

So   $x^{3}+ax^{2} -2x+a+6/(x+a)=0$

x+a ) $x^{3}+ax^{2} -2x+a+6$ ( $x^{2} -2$

        $x^{3}+ax^{2}$

        _______________

                      $-2x+a+6$

                      $-2x-2a$

                      ________

                              $3a+6$

So 3 a + 6 = 0 (Given  ( x+a ) is zero of the polynomial f(x))

=> 3 a = - 6

=> a = - 2

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