Question

please tell me the answer of both.
only that answer would be brienlest who have done both question​

Answer 1

Step-by-step explanation:

Question 6.

Solution.

11sin70°/7cos20°-4cos53°cosec37°/7tan15°tan35°tan55°tan75°

=11sin70°/7cos(90°-70°)-4cos53°cosec(90°-53°)/7tan15°tan35°tan(90°-35°)tan(90°-15°)

=11sin70°/7sin70°-4cos53°sec53°/7tan15°tan35°cot35°cot15°

=11/7-4/7

=1 Ans.

Question 7.

Solution.

From LHS

cosecA / (cosecA - 1 ) + cosecA / ( cosecA + 1 )

cosecA ( cosecA - 1 ) + cosecA ( cosecA + 1 )

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(cosecA - 1 ) ( cosecA + 1 )

cosec²A - cosecA + cosec²A + cosecA

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cosec²A - 1

2 cosec²A / cot²A

2 / sin²A

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cos²A / sin²A

2 / cos²A

= 2sec²A RHS = LHS prooved

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Hope it helps you !!!

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