please tell me this question
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just equate the matrix element
a+b=6-----(1)
5+c=-1 → c=-6
d=3
ab=8
multiply 1 st equation with a
so a²+ab=6a
a²+8=6a
a²-6a+8=0
a²-2a-4a+8=0
a(a-2)-4(a-2)=0
(a-4)(a-2)=0
So a= 4 Or 2
Also ab=8
if a =4 then b=2
And if a=2 then b=4
a+b=6-----(1)
5+c=-1 → c=-6
d=3
ab=8
multiply 1 st equation with a
so a²+ab=6a
a²+8=6a
a²-6a+8=0
a²-2a-4a+8=0
a(a-2)-4(a-2)=0
(a-4)(a-2)=0
So a= 4 Or 2
Also ab=8
if a =4 then b=2
And if a=2 then b=4
Anonymous:
plzz mark it brainliest if you like
to get ab int the eq and then substitute the value ab=8 in it
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