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Perpendicular =12m
Base=5m
Hypotenuse=by pythagorus rheorem
P^2+B^2=H^2
12^2+5^2=h^2
144+25=h^2
169=h^2
H=_/169
H=13 cm
Ht of pole =P+H
=12+13=25cm
Base=5m
Hypotenuse=by pythagorus rheorem
P^2+B^2=H^2
12^2+5^2=h^2
144+25=h^2
169=h^2
H=_/169
H=13 cm
Ht of pole =P+H
=12+13=25cm
Answered by
1
Perpendicular =12m
Base=5m
Hypotenuse=by pythagorus rheorem
P^2+B^2=H^2
12^2+5^2=h^2
144+25=h^2
169=h^2
H=_/169
H=13 cm
Ht of pole =P+H
=12+13=25cm
Base=5m
Hypotenuse=by pythagorus rheorem
P^2+B^2=H^2
12^2+5^2=h^2
144+25=h^2
169=h^2
H=_/169
H=13 cm
Ht of pole =P+H
=12+13=25cm
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