Question

Plot velocity time graph for a body whose initial velocity is 5m/s and is moving along a retardation of 1m/s^2. Also calculate the distance covered by it.

Answer 1

Here is your answer
Initial velocity = 5 ms^-1 (u)
Retardation= 1 ms^-2 (a)
Final velocity = 0 (v)
v^2= u^2 - 2aS
S= distance covered
S = 25÷2=12.5m
S= (v^2+u^2)÷2a
Substituting the values we get
Distance covered is 12.5m

Hope this helps.

Answer 2

u = 5m/s

v = 0m/s

a = -1m/s^2

S = v^2-u^2 = 0^2-5^2. = -5^2 = 25

------------. -----------. -----. ----

2a. 2×-1. -2. -2

=12.5//

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