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It has not constant d so it is not in a. P
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If
n=1
t1=4×(1)square+2
=4+2
=6
t2=4x (2)square +2
=4×4+2
=18
t3=4×(3)square +2
=4×9+2
=36 +2
=38
t4=4×(4)square+2
=4×16+2
=66
Comparing,
t2-t1=18-6=12
t3-t2=38-18=20
t4-t3=66-38=28.
It's an Arithmetic Progression as the difference between the terms is increasing by 8.
Hope it helps you!
n=1
t1=4×(1)square+2
=4+2
=6
t2=4x (2)square +2
=4×4+2
=18
t3=4×(3)square +2
=4×9+2
=36 +2
=38
t4=4×(4)square+2
=4×16+2
=66
Comparing,
t2-t1=18-6=12
t3-t2=38-18=20
t4-t3=66-38=28.
It's an Arithmetic Progression as the difference between the terms is increasing by 8.
Hope it helps you!
Anonymous:
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Thnx
wlcm
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