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Let the number of white balls in the bag be W.
Let the number of black balls in the bag be B.
Now,
Given that half, the number of white balls is equal to one-third of the number of white balls.
= > (1/2) W = (1/3)B
= > W/2 = B/3
= > 3W - 2B = 0 ----- (1)
Given that two times, the total number of balls exceed three times the no of black balls by 4.
= > 2(W + B) = 3(B) + 4
= > 2W + 2B = 3B + 4
= > 2W - B = 4 ------ (2)
On solving (1) * 2 & (2) * 3, we get
6W - 4B = 0
6W - 3B = 12
---------------------
-B = -12
B = 12.
Substitute B = 12 in (1), we get
= > 3W - 2B = 0
= > 3W - 2(12) = 0
= > 3W - 24 = 0
= > 3W = 24
= > W = 24/3
= > W = 8.
Therefore the number of black balls = 12, white balls = 8.
Hope this helps!
Let the number of black balls in the bag be B.
Now,
Given that half, the number of white balls is equal to one-third of the number of white balls.
= > (1/2) W = (1/3)B
= > W/2 = B/3
= > 3W - 2B = 0 ----- (1)
Given that two times, the total number of balls exceed three times the no of black balls by 4.
= > 2(W + B) = 3(B) + 4
= > 2W + 2B = 3B + 4
= > 2W - B = 4 ------ (2)
On solving (1) * 2 & (2) * 3, we get
6W - 4B = 0
6W - 3B = 12
---------------------
-B = -12
B = 12.
Substitute B = 12 in (1), we get
= > 3W - 2B = 0
= > 3W - 2(12) = 0
= > 3W - 24 = 0
= > 3W = 24
= > W = 24/3
= > W = 8.
Therefore the number of black balls = 12, white balls = 8.
Hope this helps!
siddhartharao77:
:-)
Answered by
1
Number of black balls= 12 and
Number of white balls = 8
Number of white balls = 8
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