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Solution-
Join AC and QP, also it is given that AQ || CP
∴ △ACQ and △APQ are on the same base AQ and lie between the same parallels AQ || CP.
∴ ar(△ACQ) = ar(△APQ)
or ar(△ABC) + ar(△ABQ)
= ar(△BPQ) + ar(△ABQ)
or ar(△ABC) = ar(△BPQ)
or 1/2 ar(||gm ABCD) = 1/2 ar(||gm PBQR)
or ar(||gm ABCD) = ar(||gm PBQR)
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