Question

pls answer fast, it's kind of urgent. pls answer in steps, I beg you, it's very urgent, somebody please help​

Answer 1

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☆ Here:-

▪︎ By EDL i.e. Euclid's Division Lemma we get,

=》 a = bq + r,

0<or equal to r<b.

☆ Now Given:-

1. a = 4q+r.

☆ To find:-

• b and r.

☆ Clearly,

▪︎ Here we can see that,

${\large{\blue{\boxed{\bold{b\:=\:4.}}}}}$

▪︎ Also we know that b>r.

${\large{\blue{\boxed{\bold{=》\:r\:=\:0,\:1,\:2,\:3}}}}}$

▪︎ Therefore b = 4 and the possible values of r are 1, 2, or 3.

☆ Now,

▪︎ When r = 0,

a = 4q, Which is an even case.

▪︎ When r = 1,

a = 4q+1, Which is an odd case.

▪︎ When r = 2,

a = 4q+2, Which is an even case.

▪︎ When r = 3,

a = 4q+3, Which is an odd case.

-----------------------------------

2.

☆ Given:-

• a = 7q+r.

☆ Therefore,

${\large{\green{\boxed{\bold{b\:=\:7}}}}}$

▪︎ And,

${\small{\green{\boxed{\bold{r\:=\:0,\:1,\:2,\:3,\:4,\:5,\:6,}}}}}$

☆ Similarly as in above cases in each of these cases also you can find that it is even or odd.

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