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In triangle ADB
AB²=AD²+BD²
13²=12²+BD²
BD²=169-144
BD=√25
BD=5
In triangle ADC
AC²=AD²+DC²
15²=12²+DC²
DC²=225-144
DC=√81
DC=9
BC=BD+DC
BC = 5+9
BD = 14
Thnx✌️✌️
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The given triangle consists of two right angle triangle.
(1) Pythagoras theorem
AC² = AD² + DC²
15² = 12² + DC²
225 = 144 + DC²
225 - 144 = DC²
81 = DC² DC = √81 •°• DC = 9cm
(2) Pythagoras theorem
AB² = AD² + BD²
13² = 12² + BD²
169 = 144 + BD²
169 - 144 = BD²
25 = BD² BD = √5 •°• BD = 5cm
BC = BD + DC = 5 + 9 = 14cm
Length for BC is 14cm
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