Question

pls answer fst .........
40 students enter for a game of shot put competition. The distance thrown ( in meters) is recorded below. [6]

Distance in m 12-13 13-14 14-15 15-16 16-17 17-18 18-19
Number of Students 3 9 12 9 4 2 1
Use a graph paper to draw an ogive for the above distribution.

Use a scale of 2 cm = 1 m on x-axis and 2 cm = 5 students on the other axis.

Hence using your graph paper find:

i) the median

ii) Upper Quartile

iii) Number of students who cover a distance which is above 16 \frac{1}{2} m

Answer 1

Answer:

Given : 40 students enter for a game of shot put competition

the distance thrown in metres   12-13 13-14 14-15 15-16 16-17 17 - 18  18-19

                              no of students  3        9        12        9     4          2         1

To Find :  mean

Solution:

distance   mid value   A=( mid value - 14.5)   f         A* f

12-13            12.5               -2                          3           -6

13-14             13.5                 -1                         9           -9

14-15            14.5                 0                         12           0

15-16            15.5                1                          9            9

16-17            16.5                2                          4             8

17 - 18          17.5                3                          2            6

18-19             18.5                4                          1             4

                                                                      40           12

14.5  +  12/40

= 14.5  + 0.3

= 14.8  

14.8 m is the mean distance

Answer 2

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