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Consider Triangle ABD
In which,
BD =AD....................given
:. it is an isosceles triangle
:./_DAB =/_ABD...... angles of an isosceles
triangle
:. 59° = /_ABD
:. 59°=/_ ABC........B-D-C
:./_ACB + /_CAB +/_ABC=180°
:./_ACB + (59°+32°) + 59° =180°
:./_ACB + 91°+59° =180°
:./_ACB + 150°=180°
:./_ACB = 180°-150°
[:./_ACB = 30°]
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