Question

pls answer it
it urgent​

Answer 1

Given:

• (P) Power= 100W
• (V) Potential Difference = 230V
• (I) Current = ?
• (R) Resistance = ?

a) Electricity flowing per second = Electric Current.....

$P = VI$

$I = P/V$

Putting all values.....

I = 100/230

I = 10/23

I = 1/2.3 A ( ampere)

b) Resistance

$R = V/I$

Putting all the values......

R = 230÷1/2.3

R = 230 × 23/10

R = 23 × 23

R = 529Ω

c) New Power ( Pn) = 25w

Reduce in the power is 75%.......

So to do so....... reduce the electric current consumption of bulb by 75%.....

Rather I am confused in this answer......

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