Question

pls answer it urgent​

Answer 1

Answer:

Given:

Mass of bullet = 10 g = 0.01 kg

Initial speed = 10³ m/s

Travels in the sand for 5 cm = 0.05 m

To find:

Average resistive force experienced by the bullet.

Calculation:

First find the acceleration of the bullet :

v² = u² + 2as

=> 2as = v² - u²

=> 2 × a × (0.05) = 0² - (10³)²

=> a = - 10^7 m/s²

Now force = mass × acceleration

=> force = 0.01 × 10^7

=> force = 10^5 N

So final answer :

$\boxed{ \blue{force = {10}^{5} newton}}$

Answer 2

Answer:

1st step :

$acc. = \dfrac{ {v}^{2} - {u}^{2} }{2s}$

=> acc = {0² - (10³)²}/(2 × 0.05)

=> acc = 10^7 m/s²

So force = m × acc.

=> force = 0.01 × 10^7

=> force = 10^5 N

Force = 10^5 N