Pls answer my question which is
A man is 20 year elder to his son. After 10 years his age becomes twice the age of his son. Find the present age
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let the age of his son = x
then the age of man = x+20
after 10 years
the age of Man is twice of the age of his son
then x+ 20 + 10 = 2(x+10)
x+ 30 = 2x + 20
30-20 = 2x -x
10 = x
the present age of man is 10 + 20 = 30years
the present age of his son is 10years
hope this helps you ....
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then the age of man = x+20
after 10 years
the age of Man is twice of the age of his son
then x+ 20 + 10 = 2(x+10)
x+ 30 = 2x + 20
30-20 = 2x -x
10 = x
the present age of man is 10 + 20 = 30years
the present age of his son is 10years
hope this helps you ....
pls mark as brainlist ....
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