Pls answer question 7
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Ans. is (b) 101 times ....
solution is in the pic...
solution is in the pic...
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kvnmurty:
very good
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Answer is 101 times.
Watch 1 ticking period = ticks every 95/90 sec =
= T1 = 19 * 5 ÷ 2 * 5 * 9 sec
Watch 2 ticking period = ticks every 323/315 s
= T2 = 19 * 17 ÷ 5 * 7 * 9 sec
T1 - T2 = 19/(5*9) [5/2 - 17/7] = 19 ÷ 2 * 5 * 7 * 9 sec
T1/ [T1 - T2 ] = 35
T2 / [T1 - T2 ] = 34
So 34 ticks of Clock 1 = 35 ticks of clock 2
Every 34 ticks of clock 1 they beat together again.
ie., every 34 * 19 * 5 / [ 2 * 5 * 9 ] sec = 17 * 19 / 9 sec
In one hour they tick together 1 + 3600 * 9/(17 * 19) times
= 101.3 times
= 101 times. Answer.
Watch 1 ticking period = ticks every 95/90 sec =
= T1 = 19 * 5 ÷ 2 * 5 * 9 sec
Watch 2 ticking period = ticks every 323/315 s
= T2 = 19 * 17 ÷ 5 * 7 * 9 sec
T1 - T2 = 19/(5*9) [5/2 - 17/7] = 19 ÷ 2 * 5 * 7 * 9 sec
T1/ [T1 - T2 ] = 35
T2 / [T1 - T2 ] = 34
So 34 ticks of Clock 1 = 35 ticks of clock 2
Every 34 ticks of clock 1 they beat together again.
ie., every 34 * 19 * 5 / [ 2 * 5 * 9 ] sec = 17 * 19 / 9 sec
In one hour they tick together 1 + 3600 * 9/(17 * 19) times
= 101.3 times
= 101 times. Answer.
:-)
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