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the angle between two vectors is
found by
let a and b two vector then angle between them
cos∅ = a.b/|a| |b|
cos∅ = ratio of dot product of two vectors and product of its magnitude .
now,
cos∅ = A.B/|A||B|
=(i + j ).( i -j)/√2.√2
=(1 -1)/2
=0
cos∅ = cosπ/2
∅ = π/ 2
found by
let a and b two vector then angle between them
cos∅ = a.b/|a| |b|
cos∅ = ratio of dot product of two vectors and product of its magnitude .
now,
cos∅ = A.B/|A||B|
=(i + j ).( i -j)/√2.√2
=(1 -1)/2
=0
cos∅ = cosπ/2
∅ = π/ 2
Answered by
1
see attachment............
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