Pls answer the following question
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according to question,
a^ + b^ = a^
take modulus both sides
a² + b² + 2abcos∅ = a²
cos∅ = -b/2a
and ( a^ + b^) is perpendicular upon a^
so, (a^ + b^ ).a^ =0
a² + a^.b^ =0
a² + ab( -b/2a) =0
a² -b²/2 =0
b² = 2a²
b = ± √2a
hence , b = √2a
a^ + b^ = a^
take modulus both sides
a² + b² + 2abcos∅ = a²
cos∅ = -b/2a
and ( a^ + b^) is perpendicular upon a^
so, (a^ + b^ ).a^ =0
a² + a^.b^ =0
a² + ab( -b/2a) =0
a² -b²/2 =0
b² = 2a²
b = ± √2a
hence , b = √2a
Answered by
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