Question

Pls answer the following question, pls

Answer 1

(1)In triangle PQR
Angle PRQ=90 degree(angle in semi circle are right angle)
angle Q=65 degree
65+90+QPR=180
QPR=180-155=25 degree.
(2)Now PQRS is a cyclic quadrilateral
so angle PQR + PSR =180
65+PSR=180
PSR=180-65=115
Now in triangle PSR
PSR + RPS +PRS =180
115+25+PRS=180
PRS=180-140=40
(3)PSR =115
(4)In triangle PQT
angle QTP=90(angles in semi circle are 90)
so 60+90+PQT=180
PQT=180-150=30
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