Question

pls answer the question ​

Answer 1

Answer:

 $\frac{8}{9}$

Step-by-step explanation:

$\frac{81^\frac{-3}{4} }{16^\frac{-3}{4} }$

$\frac{3^(^4^*^\frac{-3}{4}^) }{2^(^4^*\frac{-3}{4}^) }$

$\frac{3^-^3}{2^-^3}$

$\frac{2^3}{3^3}$

$\frac{8}{9}$

:)