Question

PLS ANSWER THIS FAST I NEED IT URGENTLY VERY FASTLY

Answer 1

side of the triangle = 15 m, 11 m and 6 m
s=15+11+6/2 = 16 m
(s-a)= (16-5)m= 1 m
(s-b)=(16-11)m=5 m
(s-c)=(16-6)m= 10 m
Area=whole root 16×1×5×10
=whole root 2×2×2×2×1×5×2×5
=20 root 2 m sq.

here is your answer.

Answer 2

let given of the wall be a = 15m,b=11m and c=6m
therefore: semi-perimeter,s=a+b+c/2
=15+11+6/2=32/2=16m
now,area of wall=
$\sqrt{s(s - a)(s - b)(s - c)}$
$\sqrt{16(16 - 15)(16 - 11)(16 - 6)}$
$20 \sqrt{2m {?}^{2} }$