Question

Pls answer this....i will mark BRAINLIEST...NO SPAM..full solution​

Answer 1

Answer:

$\frac{ \sqrt{15} - 3}{2}$

This is 100% the correct answer. As I have solved it earlier.

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Answer 2

Step-by-step explanation:

$given \\ \: \: \: \: \: \: \: \: y = \frac{1}{2 + \frac{?}{3 + \frac{1}{2 + \frac{1}{3 + ............. } } } } \\ = > y = \frac{1}{2 + \frac{1}{3 + y} } \\ = > y = \frac{1}{ \frac{6 + 2y + 1}{3 + y} } \\ = > y = \frac{3 + y}{6 + 2y + 1} \\ = > 6y + 2 {y}^{2} + y = 3 + y \\ = > 2 {y}^{2} + 6y - 3 = 0 \\ = > y = \frac{ - 6 + - \sqrt{ {6}^{2} - 4.2.( - 3)} }{2.2} \\ = > y = \frac{ - 6 + - 2 \sqrt{15} }{4} \\ = > y = \frac{ - 3 + - \sqrt{15} }{2}$

Therefore y=(-3+√15)/2 or y=(-3-√15)/2