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given that B is the mid point of AC
•3 = x+5/2
x+ 5= 6
x = 1
•4 = 2+y/2
2+y = 8
y = 6
hence the coordinates of C(1,6)
•3 = x+5/2
x+ 5= 6
x = 1
•4 = 2+y/2
2+y = 8
y = 6
hence the coordinates of C(1,6)
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