Question

Pls answer this question

Answer 1

Answer:

Step-by-step explanation:

open the identity (sin²A+cos²A)²  

as (a+b)²=a²+b²+2ab

(sin²A+cos²A)²=sin^4A+cos^4A+2sin²Acos²A        use sin²a+cos²a=1

(1)² - 2sin²Acos²A = sin^4A+cos^4A

1-2sin²Acos²A = sin^4A+cos^4A

hence proved

Answer 2

Answer:

please refer to the attachment

I hope it would help you

thank you