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Answer:
10 a internal daimeter = 4cm
internal radius =4/2=2cm
thickness of pipe =0.5cm
outer radius= inner radius +thickness of pipe=2+0.5=2.5cm
10 b
let the inner radius to be r and outer to be R
volume of material used = volume of outer cylinder - volume of inner cylinder
= πR²h - πr²h
= 22/7×2.5×2.5×8 - 22/7×2×2×8
= 157cm³-100.48cm³
= 56.52cm³
hence the volume of material required to make pipe is 56.52 cm²
10 c total surface area of pipe = l.s.a of outer cylinder + 2(area of outer cirlce-area of inner circle)+l.s.a of inner cylinder
= 2πRh+ 2(πR²-πr²)+2πrh
= 2×22/7×2.5×8 +2{(22/7×2.5×2.5)-(22/7×2×2)
+ 2×22/7×2×8
=125.7+14.08+100.57
= 240.35cm²
10 d
volume of water delivered in 20 sec = area of inner circle ×distance travlled by water in 20 sec (height of water deliverded20 sec )
speed=d/t
0.15m/s=d/1
d= 0.15m
distance travelled by water in 20 sec = 0.15×20m
=3m
putting this in formula = 3×2πr²
=3×2×22/7×2×2
= 75.42 m ³
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