Question

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Answer 1

Answer:angle ABC=10

80+90=170 (90 degree because it a right angled triangle

180 - 170 =10

Angle ACE =55

90+35=125

180 - 125=55. (LINEAR PAIR)

ANGLE ACB=90. (Right angled triangle)

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Answer 2

(i)

AB||CE (GIVEN)

AC = transversal

Therefore,

angle2 =angle BAC (alternate interior angles)

angle2 =80°

angle ACE=80°

(ii)

angle3 + angle2 + 35°=180° (Linear pair)

angle3 + 80° + 35° = 180°

angle3 = 180°- 115°

angle3 = 65°

angle ACB = 65°

(iii)

In ∆ ABC:-

80°+ angle1 + angle3 =180°(Angle sum property of ∆)

angle1 + 80°+ 65°=180°

angle1 = 180°-145°

angle1 = 35°

angle ABC = 35°

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