Question

Pls explain how to draw square root of 9.3 on no. line

Answer 1

1. Draw a line named 'AB ' with measure 9.3unit.

2. From B Add 1 cm and mark as 'C '

3. take the half of 'AC ' and mark it 'O '( means Bisect A and C and mark mid point as O)

4. take the measure of 'AO ' as radius and with 'O ' as centre draw a semi circle.( means In a semicircle O is a mid point considered as a radius)

5. And from 'B ' draw a line perpendicular to AB, touching the semi circle at D,( means from B draw a perpendicular line which meets on Semicircle at D)  and markthat point as root 9.3 .

6. Take compass pointer on B and the pencil point on D and then draw an arc on no. line 

7. Hence mark on no. line as root 9.3 

Answer 2

first,take 9.3 in a scale and draw a line then mark AB
then,take 1 cm extra and mark C
now find the mid point of the whole line
draw a semi circle in that line with that point
after,draw a line from point B to D ( D is the point in semi circle
after all draw a arc from point B to no line
this is the correct location of √9.3