pls explain me how to solve this question....
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First of all form an equation of the base.
A (4,-2) and B (7,2)
equation is given by : (y - y1)/(y2 - y1) = (x - x1)/(x2 - x1)
I took y1 = -2, y2 = 2 and x1 = 4 and x2 = 7
Substitute the value and you will get the equation as 3y - 4x +22 = 0
Now drop a perpendicular from C to AB which touches AB at M
C (-3,5)
CM = mod of [{(3*-3)+(-4*5)+22} / sqrt(9+16)]
Solve this and you will get CM as 7/5
A (4,-2) and B (7,2)
equation is given by : (y - y1)/(y2 - y1) = (x - x1)/(x2 - x1)
I took y1 = -2, y2 = 2 and x1 = 4 and x2 = 7
Substitute the value and you will get the equation as 3y - 4x +22 = 0
Now drop a perpendicular from C to AB which touches AB at M
C (-3,5)
CM = mod of [{(3*-3)+(-4*5)+22} / sqrt(9+16)]
Solve this and you will get CM as 7/5
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