Math, asked by ga6556744, 1 year ago

Pls fast for exams
Simplify

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Answered by NeelamG
1

c) a^0= 1

(3^0-2^0)×6^0= (1-1)×1= 0

d) .

 \frac{ {5}^{3}  \times  {3}^{5} \times 6 }{ {3}^{2} \times 25 }  =  \frac{ {5}^{3} \times   {3}^{5} \times 6 }{ {3}^{2} \times  {5}^{2}  }  \\  =  {5}^{3 - 2}  \times  {3}^{5 - 2}  \times 6 = 5 \times  {3}^{3}  \times 6 \\  = 810

e)

 \frac{ { ({5}^{2} })^{3}  \times  {5}^{4} }{ {5}^{5} }  =   \frac{ {5}^{3 \times 2}  \times  {5}^{4} }{ {5}^{5} }  \\  =  {5}^{6}  \times  {5}^{4}  \times  {5}^{ - 5} \\  =  {5}^{6 + 4 - 5}  =  {5}^{5}


NeelamG: i hope it will help u
ga6556744: Yes. Thnx
ga6556744: I got answer don't write answer now (anyone)......
NeelamG: you told me
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