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Find the value of a²/bc+b²/ac+c²/ab if a+b=-c
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Given a + b = -c.
On cubing both sides, we get
= > (a + b)^3 = (-c)^3
= > a^3 + b^3 + 3ab(a + b) = -c^3
= > a^3 + b^3 + 3ab(-c) = -c^3
= > a^3 + b^3 + c^3 = 3abc ------ (1)
Now,
= > (a^2/bc) + (b^2/ac) + (c^2/ab)
= > (a^3 + b^3 + c^3)/abc
= > 3abc/abc
= > 3.
Hope this helps
siddhartharao77:
it was copied from nextgurukul...
If u want to become a brainly teacher, u should be a teacher in real life or ur age should be 18+
they will contact ur (or) they will come to know by seeing ur answers i.e the way ur answering
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