pls give answer correctly,i will merk as Brainlliest
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Perimeter of rhombus=80cm
So, Side of rhombus=20cm
Since, perimeter is the sum of all Sides
Diagonals of rhombus are perpendicular bisectors of each other.... So, by Pythagoras at center(let, O) we get...
AB^2=AO^2+BO^2
20^2=6^2+BO^2
BO^2=2√91
So, d2=4√91
Now, area of rhombus = 1/2*d1*d2 = 1/2*12*4√91 = 24√91
Area of rhombus is 24√91
hope this helps you
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