Math, asked by Mnopq11, 1 year ago

Pls help.....
Correct answer will be marked as the brainliest

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Answers

Answered by Anonymous
2
[(243)^13/100 × (243)^7/100]/[(7)^25/100 × (7²)^75/1000 × (7³)^2/10].
[243^13/100+7/100] /[ 7^25/100+150/1000+6/10]
(using formula (a^m)^n = a^mn) and (a^m × a^n = a^m+n)

[(243)^20/100] / [7^1000/1000]
(243^1/5) / 7¹
(3^5)^1/5 / 7
3/7 is the answer
hope this helps
any confusion then message me ......


Mnopq11: Thanks very much! !!!!
Anonymous: ur welcome....
Answered by AishikTokdar
0
[(243)^13/100 × (243)^7/100]/[(7)^25/100 × (7²)^75/1000 × (7³)^2/10].
[243^13/100+7/100] /[ 7^25/100+150/1000+6/10]
(using formula (a^m)^n = a^mn) and (a^m × a^n = a^m+n)

[(243)^20/100] / [7^1000/1000]
(243^1/5) / 7¹
(3^5)^1/5 / 7
3/7 is the answer
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