Question

pls help for 20 pts​

Answer 1

Answer:

(i) n = -1

(ii) n = 4

Step-by-step explanation:

(i) RHS --> ∛8 ÷ (2³)^2/3

=> 2 ÷ 2^[3*(2/3)]

=> 2 ÷ 2² => 2 ÷ 4 => 1/2 which is $2^{-1}$

As LHS = RHS, $2^{n}$ = $2^{-1}$.

Comparing, n = -1.

(ii) m = 16

LHS --> $16^{\frac{3}{4}$

=> $2^{4}^\frac{3}{4}$ => 2^[4*(3/4)] => 2³ => 8

RHS --> $8mn^{1/3}$

=> $(8*16n)^{1/3}$

As LHS = RHS, 8 = $(8*16n)^{1/3}$

=> 8³ = $[(8*16n)^{1/3}]^3$                         (Cubing both sides)

=> 512 = 8*16n

=> 512 = 128n

∴ n = 512/128 => 4

Answer 2

Answer:

Sorry don't know

Step-by-step explanation: