Math, asked by vasanthsandesh18, 1 month ago

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Answered by sharvindsouza535
0

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Answered by sg693363
0

Answer:

(i) x = 3/7 ; (ii) x = 3 ; (iii) n = 60/71 ; (iv) n= 1 ; (v) x = 5 ; (vi) x = 0 ; (vii)  x = 1

Step-by-step explanation:

(i) x/3 + 2/7 = 2x/7 + 15/49

  2x/7 - x/3 = 2/7 - 15/49

  Taking LCM,

  (6x - 7x)/21 = (14 - 15)/49

  -x/21 = -1/49

  x = 21/49

  x = 3/7

(ii) 2x/7 + 1/7 = 2x/3 - 1

    2x/7 - 2x/3 = -1/7 - 1

    Taking LCM,

    (6x - 14x)/21 = (-1 - 7)/7

    -8x/21 = -8/7

     x = (-8/7) × (-21/8)

     x = 3

(iii) 5n/4 - n/5 +2n/15 = 1

    Taking LCM,

    (75n - 12n + 8n)/60 = 1

    83n - 12n = 60

    71n = 60

    n = 60/71

(iv) 7n/3 - 5n/6 + 8n/9 = 43/18

    Taking LCM,

    (42n - 15n + 16n)/18 = 43/18

    (58n - 15n)/18 = 43/18

    43n/18 = 43/18

    n = 43/18 × 18/43

    n= 1

(v) 2x + 15 - 4x/5 = 22 - x/5

    2x - 4x/5 + x/5 = 22 - 15

    Taking LCM,

    (10x - 4x + x)/5 = 7

    7x = 35

    x = 35/7

    x = 5

(vi) (x - 7)/7 = (x - 5)/5

     5(x - 7) = 7(x - 5)

     5x - 35 = 7x - 35

     5x - 7x = -35 + 35

     -2x = 0

      x = 0

(vii) (3x - 5)/2 = (5x - 8)/3

     3(3x - 5) = 2(5x - 8)

     9x - 15 = 10x - 16

     9x - 10x = -16 + 15

     -x = -1

      x = 1

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