Chemistry, asked by sahed123, 1 year ago

pls help me iys urjnt

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Answered by shrikant43703
1
for KCl
Kappa k= cell constant×1/R
0.00276= Cc×1/82.4
cc=0.00276×82.4=0.227
for K2 SO4
Kappa=cc×1/R =0.227×1/325
= 0.00699
then Molar conductivity=k×1000/Concentration
0.00699×1000/0.0025=2796
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