Math, asked by sairajsawant1904, 5 hours ago

pls help me with this one its a simultaneous equation​

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Answers

Answered by aliabidi09
1

Answer:

Step-by-step explanation:

Multiplying equation one by 3 we get

x + 3y = 10  ___________(1)

Multiplyinng 2nd equation by 4 we get

8x + y = 11  ---------------------(2)

Now multiplying equation 1 by 8 on both side

8x + 24y = 80 --------------------- (3 )

Subtracting equation 2 from equation 3

8x + 24y - (8x + y ) = 80 -11

24y - y = 69

23y = 69

Y = 3

put value y = 3 in equation 1 we get

x + 3 (3) = 10

x + 9 = 10

x = 10 -9

x = 1

Solutions are ( 1, 3)

Answered by vedika106
1

Step-by-step explanation:

1/3x + y =10/3 (1)

2x + 1/4y = 11/4 (2)

Multiplying (1) by 3 we get ,

x + 3y = 10 (3)

Multiplying (2) by 4 we get,

8x + y = 11 (4)

Now, to eliminate y we will multiply (4) by 3

24x + 3y = 33 (5)

By Elimination method ,

Subtracting (3) from (5)

24x + 3y - ( x + 3y) = 33 - 10

24x + 3y - x - 3y = 23

23x = 23

x = 23/23

• x = 1

Putting the value of x in (3)

x + 3y = 10

1 + 3y = 10

3y = 10-1

3y = 9

y = 9/3

• y = 3

IF THIS HELPED YOU THEN PLEASE MARK ME BRAINLIEST.

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