Question

Pls help with this two questions step by step explanation is needed

Answer 1

1 . there are two conditions

1st condition

ratio = 3:1:8

= 3x : x : 8x

= 12x

2nd condition

ratio = 1: 3:2

= x + 3x + 2x

= 6x

Divide both ratios by the options

8 is greater value .

It is given by (D) $96.

2. Consider ∆ADE and ACB ,

Since DE || CB,

<ADE = <ACB

<ACB = 128°

Now consider ∆ACB

it is an isosceles ∆

<ABC = <BAC = 180 - 128 / 2

= 54/2

= 27°

<BAC = 27°