Question

PLS HELP |x+2|<|x+1| I need the directions to though

Answer 1

Answer:

x ∈ ( - ∞ , - 3/2)

Step-by-step explanation:

|x+2| < |x+1| ⇔ (x + 2)² < (x + 1)²

(x + 2)² - (x + 1)² < 0

x² + 4x + 4 - x² - 2x - 1 < 0

2x + 3 < 0

x < $-\frac{3}{2}$

or - ∞ < x < $-\frac{3}{2}$

Answer 2

Hola mate

Here is your answer -

x + 2 = 0

x = -2 -----1

x +1 = 0

x = -1 ------2

From 1 and 2 we get :  

x + 1 is greater as -1 is greater than -2