Question

pls hlp me
will mark u as brainliest​

Answer 1

Answer:

Sorry sorry sorry sorry sorry.......... I am studying in class 7.........Please please please please please please please mark as brainliest

Answer 2

Answer:

The answer is:   a->  +-(3-2i)

Step-by-step explanation:

Suppose that a+bi is a square root of 5 + 12i.  

Then, (a+bi)^2 = (a^2 - b^2) + (2ab)i = 5 + 12i.  

Equate real and imaginary parts:  

a^2 - b^2 = 5  

2ab = 12 ==> b = 6/a.  

So, a^2 - (6/a)^2 = 5  

==> a^2 - 36/a^2 = 5  

==> a^4 -5a^2 - 36 = 0.  

==> (a^2 -9)(a^2 + 4) = 0.  

Since a must be real, a = 3 or -3.  

This gives b = 2 or -2, respectively.  

Thus, we have two square roots: 3+2i or -3-2i.