Question

pls refer picture given below

Answer 1

♠ ANSWER :

Sin² 20 ° + sin ² 70 / sin θ cos (90 - θ ) + cos θ sin ( 90 - θ )

➡️Sin² ( 90 - 70 ) + Sin ² 70 / sin θ sin θ + cos θ cos θ

➡️ Cos ² 70 + sin ² 70 / sin ² θ + cos ² θ

➡️ 1 / 1

➡️1.

Answer 2

w.k .T......
sin²70=cos²(90-70)=cos²20

so my!numerator becomes sin²20+cos²20=1
denominator becomes sin²x+cos²x=1


so answer is 1


HOPE IT HELPS...