pls solve !!!!!!!!!!
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(0,Y)
k:1 divides the line seg p(-4,5)and q(3,-7)
kx2+x1/k+1 , ky2+ky1/k+1
(0,y)=(3k-4/k+1 , -7k+5/k+1)
3k-4/k+1 =0 -7k+5/k+1=y
3k-4=0 -7(4/3)+5=y
k=4/3 -28/3+5=y
-28+15=3y
-13=3Y
y=-13/3
k:1 divides the line seg p(-4,5)and q(3,-7)
kx2+x1/k+1 , ky2+ky1/k+1
(0,y)=(3k-4/k+1 , -7k+5/k+1)
3k-4/k+1 =0 -7k+5/k+1=y
3k-4=0 -7(4/3)+5=y
k=4/3 -28/3+5=y
-28+15=3y
-13=3Y
y=-13/3
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