Question

pls
solve
hhfxghxdgfxyjvhjcgchj​

Answer 1

Answer:

$\angle EDQ = 91°\\\angle DEF = 89°\\\angle PDQ = 89°\\\angle AED = 27°$

Step-by-step explanation:

$\angle \: PDC = \angle AED = 27° \: (corresponding \: angle \: of \: DC \: and \: AE \: ) \\ \\ \angle DEA + \angle DEF + \angle FEB= 180°(linear \: pairs) \\ \\ 27° + \angle DEF + 64° = 180° \\ \\ \angle DEF = 180° - 91° \\ \\ \angle DEF = 89°$

now

$\angle DEF = \angle PDQ = 89° \: \\ (corresponding \: angles \: of \: parallel \: lines \: EF \: and \: DQ)$

now

$\angle EDQ + \angle DEF= 180° \\ (consecutive \: interior \: angles) \\ \\ \angle EDQ + 89°= 180° \\ \\ \angle EDQ = 180° - 89° \\ \\ \angle EDQ = 91°$

Hope it helps you.

Answer 2

Answer:

91° is ur answer

I hope I hope it will help you yaar

Have a great day and take care stay safe yaar ❤️❤️❤️