pls solve it.......
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HEY THERE!!!
Question:
if the sum of first n terms of an ap is given by sn=3n²+2n find the nth term?
Method Of Solution:
Let to first term of Arithmetic Sequence or Progression 'a'.
Let to common Difference of Arithmetic Progression 'd' and it's nth terms be 'n'
Here, n denotes 'Number Of terms of Arithmetic Sequence or Progression".
According to the Question;
Given:
Sequence:
Sn = 3n²+2n
To find = nth term ?
Here,
Using Formula of Tn
Formula: Tn = Sn-1 - Sn
Substitute the value of n replace n-1
Tn= Sn-1 - Sn
=> 3n²+2n
=> 3(n-1)²+2(n-1) - (3n²+2n)
=> 3(n²+1-2n)+2n-2 -( 3n²+2n)
=> 3n²+3-6n+2n-2 -3n²-2n
=> -6n-2n+2n+3-2
=> -8n+2n+1
=> -6n+1
=> 1-6n
Hence, rth term = 6n-1
Question:
if the sum of first n terms of an ap is given by sn=3n²+2n find the nth term?
Method Of Solution:
Let to first term of Arithmetic Sequence or Progression 'a'.
Let to common Difference of Arithmetic Progression 'd' and it's nth terms be 'n'
Here, n denotes 'Number Of terms of Arithmetic Sequence or Progression".
According to the Question;
Given:
Sequence:
Sn = 3n²+2n
To find = nth term ?
Here,
Using Formula of Tn
Formula: Tn = Sn-1 - Sn
Substitute the value of n replace n-1
Tn= Sn-1 - Sn
=> 3n²+2n
=> 3(n-1)²+2(n-1) - (3n²+2n)
=> 3(n²+1-2n)+2n-2 -( 3n²+2n)
=> 3n²+3-6n+2n-2 -3n²-2n
=> -6n-2n+2n+3-2
=> -8n+2n+1
=> -6n+1
=> 1-6n
Hence, rth term = 6n-1
Anonymous:
Explained
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